2a+[a-(b-c)]-[2a-(b-c)]=

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Solution for 2a+[a-(b-c)]-[2a-(b-c)]= equation:


Simplifying
2a + [a + -1(b + -1c)] + -1[2a + -1(b + -1c)] = 0
2a + [a + (b * -1 + -1c * -1)] + -1[2a + -1(b + -1c)] = 0
2a + [a + (-1b + 1c)] + -1[2a + -1(b + -1c)] = 0

Remove brackets around [a + -1b + 1c]
2a + a + -1b + 1c + -1[2a + -1(b + -1c)] = 0
2a + a + -1b + 1c + -1[2a + (b * -1 + -1c * -1)] = 0
2a + a + -1b + 1c + -1[2a + (-1b + 1c)] = 0
2a + a + -1b + 1c + [2a * -1 + -1b * -1 + 1c * -1] = 0
2a + a + -1b + 1c + [-2a + 1b + -1c] = 0

Reorder the terms:
2a + a + -2a + -1b + 1b + 1c + -1c = 0

Combine like terms: 2a + a = 3a
3a + -2a + -1b + 1b + 1c + -1c = 0

Combine like terms: 3a + -2a = 1a
1a + -1b + 1b + 1c + -1c = 0

Combine like terms: -1b + 1b = 0
1a + 0 + 1c + -1c = 0
1a + 1c + -1c = 0

Combine like terms: 1c + -1c = 0
1a + 0 = 0
1a = 0

Solving
1a = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Divide each side by '1'.
a = 0

Simplifying
a = 0

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